Write a Python program to get next day of a given date.
Code:
year = int(input("Input a year: "))
if (year % 400 == 0):
leap_year = True
elif (year % 100 == 0):
leap_year = False
elif (year % 4 == 0):
leap_year = True
else:
leap_year = False
month = int(input("Input a month [1-12]: "))
if month in (1, 3, 5, 7, 8, 10, 12):
month_length = 31
elif month == 2:
if leap_year:
month_length = 29
else:
month_length = 28
else:
month_length = 30
day = int(input("Input a day [1-31]: "))
if day < month_length:
day += 1
else:
day = 1
if month == 12:
month = 1
year += 1
else:
month += 1
print("The next date is [yyyy-mm-dd] %d-%d-%d." % (year, month, day))
if (year % 400 == 0):
leap_year = True
elif (year % 100 == 0):
leap_year = False
elif (year % 4 == 0):
leap_year = True
else:
leap_year = False
month = int(input("Input a month [1-12]: "))
if month in (1, 3, 5, 7, 8, 10, 12):
month_length = 31
elif month == 2:
if leap_year:
month_length = 29
else:
month_length = 28
else:
month_length = 30
day = int(input("Input a day [1-31]: "))
if day < month_length:
day += 1
else:
day = 1
if month == 12:
month = 1
year += 1
else:
month += 1
print("The next date is [yyyy-mm-dd] %d-%d-%d." % (year, month, day))